Ti springs

Author Message
flag Wilson4
Posted: Dec 3, 2007 at 10:02 Quote
Do you know how spring rate works. 500 x 3, for every inch it takes 500 pounds. So for 3 inches 1500 pounds. 1000 pounds for 2 and 500 for one. That's not progressive.
flag DavidMakalaster
Posted: Dec 3, 2007 at 10:03 Quote
Wilson4 wrote:
Do you know how spring rate works. 500 x 3, for every inch it takes 500 pounds. So for 3 inches 1500 pounds. 1000 pounds for 2 and 500 for one. That's not progressive.

Thank you.
flag huckoveraduck
Posted: Dec 3, 2007 at 10:07 Quote
spring rate isn't a constant figure.

so you compress a 500lb spring by 1 inch.
then you compress the same spring by 4 inches.

your saying that it is as easy to compress 4 inches as it is 1 inch

steel springs get harder the more they are compressed. thats what i am saying all along.
flag DavidMakalaster
Posted: Dec 3, 2007 at 10:10 Quote
I'm not wasting any more time on this. It's a waste of my time. Anyone with any reading comprehension will know what to believe here.
flag huckoveraduck
Posted: Dec 3, 2007 at 10:11 Quote
mtbman1980 wrote:
lol do you know how a spring works?

use google do some reseach on spring theory then get back to me

spring mechanics are easy - a spring is just a mechanical device that stores potential kinetic energy. this is high school stuff.
flag DavidMakalaster
Posted: Dec 3, 2007 at 10:13 Quote
Explain to me what you think the term pounds per inch means.
flag mtbman1980
O+ FL
Posted: Dec 3, 2007 at 10:13 Quote
if you think its that easy then why dont you understand that material properties of ti and steel dont effect the spring rate
flag huckoveraduck
Posted: Dec 3, 2007 at 10:15 Quote
DavidMakalaster wrote:
Explain to me what you think the term pounds per inch means.

pounds per inch is a measure of pressure.
flag huckoveraduck
Posted: Dec 3, 2007 at 10:16 Quote
mtbman1980 wrote:
if you think its that easy then why dont you understand that material properties of ti and steel dont effect the spring rate

because they do affect spring rate.

your trying to say the materials dont matter. so lets get a Lead spring and see how it fares up against a Steel one.
flag DavidMakalaster
Posted: Dec 3, 2007 at 10:17 Quote
huckoveraduck wrote:
DavidMakalaster wrote:
Explain to me what you think the term pounds per inch means.

pounds per inch is a measure of pressure.

Try again and if you are capable don't dumb it down so much.
flag huckoveraduck
Posted: Dec 3, 2007 at 10:19 Quote
DavidMakalaster wrote:
huckoveraduck wrote:
DavidMakalaster wrote:
Explain to me what you think the term pounds per inch means.

pounds per inch is a measure of pressure.

Try again and if you are capable don't dumb it down so much.

wow feel free to enlighten me then.
your clearly a retard when there is no such term as 'pounds per inch'

there is however pounds per square inch, which is a measure of pressure.
flag DavidMakalaster
Posted: Dec 3, 2007 at 10:22 Quote
Someone already explained it. Spring rate is the amount of force it takes to compress the spring 1 inch. For a 400 pound spring it would be 400 pounds for the first inch, 800 pounds for the second inch and 1200 pounds for the third inch. Does that make sense to you? You are burying yourself here.
flag DavidMakalaster
Posted: Dec 3, 2007 at 10:23 Quote
lbs per inch is the measurement used to express spring rate. And I'm the retard. Big Grin
flag mtbman1980
O+ FL
Posted: Dec 3, 2007 at 10:24 Quote
For a spring it has to do with how the material reactes to the shear and bending.If you exceed these then it will be dammaged. Now you have to choose materials that meet the properties that we are looking at not out of the scope of the discussion

Ti deals with these forces better thats why they dont need as many coil hence the lighter weight.
flag huckoveraduck
Posted: Dec 3, 2007 at 10:25 Quote
listen buddy - there is no such thing as 'pounds per inch'
it doesnt exist!!! you have made it up yourself.

and if it did exist - it would be a measurement of pressure. similar to pound per square inch.

thank you and good night, you are clearly a 13 year old child with no science or mathematical skill.

 


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