How so... You wan't to know how far from take off to the top of the landing this is what you would use (in a perfect world)But you would most likely need to use Cos law for anything other then a road gap (road gap would in some cases have the 90 deg angle).
are you trying to find out how fast he'll have to go to clear 17 by 25 feet..? cause i don't understand the purpose of your angles, enlighten me if i'm wrong, but he's leaving the take off at a 0 degree angle, are you trying to calculate the angle of the landing? because if you're just trying to find the velocity's you would use your vertical velocities to find time and then the time and horizontal displacement to find horizontal velocity, am i correct?
You don't need the distance of x. You will still be traveling in the x direction at, as close as makes no difference, the same velocity after you leave the ramp and the only distance you're trying to cover is 25ft. Y direction travel is incidental since it wont effect your x direction movement. Sure it's nice to know x but for what; I can't think of any reason to have it. Furthermore, using A^2+B^2=C^2 allows you to find it without a calculator. I'm not trying to deface or be flippant, don't take this as insult. Tis a good picture nonetheless.