testing for a 130 foot gap jump

 x=V0tcosθ
y=−12gt2+v0tsinθ
where the v0 is the initial velocity. and θ is the angle of thrown object (the bike and biker at around 235lbs grand total)

if we want to get the equation without the time we will have:

y=−gx22V2cos2(θ)+xtanθ
calculate that the place that the bike is thrown (or jumped) the (0,0) point. and g is the acceleration that you defined in your "engine" (the gravity, I'm sure you know what the amount is in your pedal speed is zero because gravity is faster than you can pedal here). and you know the θ then all you need to do is to put the (x,y) and calculate the velocity. before that we define a new variable h′ this way:

h′=h−**[height of my main ramp]**

and then we put it in the main formula like this:

h′=−gL22V2cos2(θ)+Ltanθ
so the velocity will be equal to:

V=−gL2(h′−Ltanθ)∗2cos2θ−−−−−−−−−−−−−−−−−−√

ergo ---- a 22 foot long ramp at 5-1/2 feet high, traveling at 57.5mph will give you the distance of ~130 feet (give or take an inch or two). not counting wind speed and other variables (like air temp, bugs hitting you in the face, etc)

 That is nuts scary just to watch

 Your going to need to pedal Sir..

 130 feet = 43m???